http://mathfactor.uark.edu/2011/01/the-nth-day-of-christmas/ The Math Factor Podcast Site Fri, 08 Aug 2014 12:52:06 +0000 hourly 1 https://wordpress.org/?v=4.9.25 http://mathfactor.uark.edu/2011/01/the-nth-day-of-christmas/comment-page-1/#comment-847 Sat, 05 Feb 2011 22:28:27 +0000 http://mathfactor.uark.edu/?p=1279#comment-847 I didn’t know that you repeat the previous gifts for each day.  I just thought it was re-describing what had already been given.  That’s what I get for being Jewish.  :)

]]> http://mathfactor.uark.edu/2011/01/the-nth-day-of-christmas/comment-page-1/#comment-844 Thu, 20 Jan 2011 05:09:49 +0000 http://mathfactor.uark.edu/?p=1279#comment-844 We can take this a step further and determine the derivative for the equation. This would be: (3/6)*N^2+N+(1/3)
 

]]> http://mathfactor.uark.edu/2011/01/the-nth-day-of-christmas/comment-page-1/#comment-842 Sat, 08 Jan 2011 06:29:09 +0000 http://mathfactor.uark.edu/?p=1279#comment-842 I found the answer using an old friend [spoiler]Pascal’s Triangle[/spoiler]

]]> http://mathfactor.uark.edu/2011/01/the-nth-day-of-christmas/comment-page-1/#comment-841 Tue, 04 Jan 2011 18:35:36 +0000 http://mathfactor.uark.edu/?p=1279#comment-841 Clarification (spoiler free):
 
What threw me off on this was that I forgot that the gifts “re-total” every day. For instance, on the 3rd day of Christmas, the true love in question gifts three french hens, two turtle doves, and a partridge in a pear tree. This is in addition to the two french hens and partridge (+ tree) from day 2 and the partridge (+ tree) from day 1, bringing the total accumulated gifts on day 3 to 3 french hens, 4 turtle doves, and 3 partridges (plus pear-producing perennials).
 
Otherwise the math is too easy and not as much fun. :-)

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