Comments on: Yoak: Wheel Whepair http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/ The Math Factor Podcast Site Fri, 08 Aug 2014 12:52:06 +0000 hourly 1 https://wordpress.org/?v=4.9.25 By: Sean McCloskey http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-726 Mon, 22 Feb 2010 19:30:53 +0000 http://mathfactor.uark.edu/?p=1014#comment-726 I guess my last post was a violation of the rules since it said to cut “a” piece, not two pieces.  But if you cut one piece with reflection symmetry containing both the true center of the wheel in one half of the piece, and the misplaced hole at the corresponding location of the other half of the piece, you can then flip this piece over and glue it back into place.  This is sort of similar to Joe’s answer since if the piece also has rotational symmetry, then you can rotate it instead of flipping it over.

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By: Sean http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-724 Sat, 20 Feb 2010 07:07:38 +0000 http://mathfactor.uark.edu/?p=1014#comment-724 Fourth solution:  Cut a shape containing the center of the circle and a congruent shape containing the incorrect hole and swap them.

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By: Sean http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-723 Sat, 20 Feb 2010 06:42:09 +0000 http://mathfactor.uark.edu/?p=1014#comment-723 Third solution:  Cut (rather than drill) a one-inch hole in the center of the wheel.  Remove and use to plug in the incorrectly placed hole.

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By: Stephen Morris http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-722 Fri, 19 Feb 2010 22:54:43 +0000 http://mathfactor.uark.edu/?p=1014#comment-722 No significance to my spelling puzzle with three z’s.  This one woke me up!

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By: Stephen Morris http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-721 Fri, 19 Feb 2010 22:52:40 +0000 http://mathfactor.uark.edu/?p=1014#comment-721 Another intreaguing puzzzle.

I came up with Sean’s solution and assumed that was what Jeff had in mind.  I completely missed Joe’s.

The point of Sean’s solution is symmetry.  The original circle and the circle centred on the hole are identical but off-set by two inches.  They overlap each other in a symmetrical way.  The two areas which are in one circle, but not the other, are identical crescent shapes.  Adding either crescent to the overlapping region will give one of the two circles.

I thought this was very neat!

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By: jyoak http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-720 Fri, 19 Feb 2010 19:51:45 +0000 http://mathfactor.uark.edu/?p=1014#comment-720 Joe’s solution is equivalent to the one that I had in mind.  I’m still trying to decide if Sean’s solution works.  I had originally thought not which is what make the puzzle interesting to me.

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By: Joe http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-719 Fri, 19 Feb 2010 00:23:29 +0000 http://mathfactor.uark.edu/?p=1014#comment-719 Another solution:  Pick a point in the wheel that is equally distant from the center of the wheel and the hole, and is closer to the center than the edge. Cut out a circle, centered at this point, which is large enough to contain the whole. Then rotate this circle until the whole is in the center of the wheel, then glue.

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By: Sean http://mathfactor.uark.edu/2010/02/yoak-wheel-whepair/comment-page-1/#comment-718 Wed, 17 Feb 2010 07:15:07 +0000 http://mathfactor.uark.edu/?p=1014#comment-718 Take a compass and center it at the off-center hole.  Open it to a radius of 5 inches and trace a circle.  The circle will intersect with the wood, drawing a crescent along one side.  Cut this crescent from the circle with the laser and move it over the other side of the piece of wood, then glue.

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